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The running difference

For each card CCC, let d(C)d(C)d(C) be its red number minus its blue number, and put M=n−1M=n-1M=n−1. Then ∣d(C)∣≤M|d(C)|\le M∣d(C)∣≤M.

Both colors have the same total, so ∑Cd(C)=0\sum_C d(C)=0∑C​d(C)=0. If the cards already picked up have total difference SSS, the remaining cards have total difference −S-S−S.