#####   ######  #####    ###    #   #  ###  #   #  ######
##  ##  ##      ##  ##  ## ##   #   #   #   #   #  ##
#####   ####    #####   #   #   #   #   #   #   #  ####
##  #   ##      ##      ## ##    # #    #    # #   ##
##   #  ######  ##       ###      #    ###    #    ######

$ curl repovive.com/roadmaps/go/loops/practical-example-fizzbuzz

░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░████████████████████████████████████████████████████████████████

#####   ######  #####    ###    #   #  ###  #   #  ######
##  ##  ##      ##  ##  ## ##   #   #   #   #   #  ##
#####   ####    #####   #   #   #   #   #   #   #  ####
##  #   ##      ##      ## ##    # #    #    # #   ##
##   #  ######  ##       ###      #    ###    #    ######

$ curl repovive.com/roadmaps/go/loops/practical-example-fizzbuzz

Repovive

Practical Example: FizzBuzz - Loops | Go | Repovive

Repovive.

Go10 sections · 431 units20h total

Open in Course

Practical Example: FizzBuzz

Classic problem

FizzBuzz demonstrates loop logic:

for i := 1; i <= 15; i++ {
    switch {
    case i%15 == 0:
        fmt.Println("FizzBuzz")
    case i%3 == 0:
        fmt.Println("Fizz")
    case i%5 == 0:
        fmt.Println("Buzz")
    default:
        fmt.Println(i)
    }
}

Print Fizz for multiples of $3$ , Buzz for $5$ , FizzBuzz for both, otherwise the number.