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Let G be a connected simple graph with 2n vertices, where n≥2.
For two distinct vertices u and v, let c(u,v) be the minimum number of edges that must be removed to disconnect u from v.
For each vertex v, consider the 2n−1 values c(v,u) over all other vertices u. Let b(v) be the sum of the n smallest values.
Arrange all vertices around a circle. The cost of an arrangement is the sum of c(u,v) over all consecutive pairs, including the last and first vertices. Consecutive vertices do not need to be adjacent in G.
Prove that the minimum possible cost is
2v∈V(G)maxb(v).You can write formulas in LaTeX or in plain text, and write your solution in any language.