Sometimes you need to reverse only a portion of a list—nodes from position to .
The approach:
Find the node before position (call it prev)
Reverse the sublist from to
Reconnect: prev.next points to new sublist head, old sublist head points to node after
# After finding prev and the sublist
# Reverse the sublist, track its new head and tail
# Reconnect
prev.next = newSublistHead
oldSublistHead.next = nodeAfterN
This combines traversal, reversal, and careful pointer management. Practice until it becomes natural.