The DP gives minimum cuts. What about finding all palindrome partitions? Use backtracking with the table. At each position, try all palindromic prefixes.
For "aab": start at . "a" is palindrome → recurse on "ab". "aa" is palindrome → recurse on "b". "aab" is not. Collect all valid partitions: [["a", "a", "b"], ["aa", "b"]]. Time: exponential in worst case. The time complexity is exponential because the number of valid partitions can be exponential.