Implement it on LeetCode. Alternative: use Kahn's algorithm (BFS-based topological sort). Count in-degrees, process nodes with in-degree . If you process all nodes, no cycle exists. text function canFinish(numCourses, prerequisites): compute in-degree for each course queue = courses with in-degree 0 processed = 0 while queue not empty: course = queue.pop() processed++ for each dependent course: in-degree[dependent]-- if in-degree[dependent] == 0: queue.add(dependent) return processed == numCourses
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$ curl repovive.com/roadmaps/maang-interview-prep/graphs/course-schedule-implementation
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