Implement it on LeetCode. The tricky parts: Skipping duplicates for the first element: if nums[] == nums[-], skip Skipping duplicates after finding a triplet: move both pointers past duplicate values The outer loop only goes to - (need room for elements) This problem combines sorting, two pointers, and careful duplicate handling. Know it well.
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$ curl repovive.com/roadmaps/maang-interview-prep/two-pointers-sliding-window/3sum-implementation
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