Math Fundamentals18 sections · 814 units
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Geometric Series Formula

Sum of geometric sequence

The sum of a geometric sequence a,ar,ar2,...,arn1a, ar, ar^2, ..., ar^{n-1} equals S=a×rn1r1S = a \times \frac{r^n - 1}{r - 1} when r1r \neq 1.

For example, 1+2+4+8+161 + 2 + 4 + 8 + 16 has a=1a = 1, r=2r = 2, n=5n = 5. So S=1×25121=3211=31S = 1 \times \frac{2^5 - 1}{2 - 1} = \frac{32 - 1}{1} = 31.

When r=1r = 1, all terms are the same, so the sum is just a×na \times n. The formula breaks down because you'd divide by zero.