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$ curl repovive.com/roadmaps/python/making-decisions/fizz-buzz-implementation

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$ curl repovive.com/roadmaps/python/making-decisions/fizz-buzz-implementation

Repovive

Fizz Buzz - Implementation - Making Decisions | Python | Repovive

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Python9 sections · 462 units23h total

Open in Course

Fizz Buzz - Implementation

The solution

Here's the correct implementation:

for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)

We check "both" first, then "only $3$ ", then "only $5$ ", then neither. This ordering ensures each number gets exactly the right output.

Alternative: check i % 15 == 0 for FizzBuzz, since $15$ is the LCM of $3$ and $5$ .