Implement it on LeetCode. To reconstruct the actual LCS (not just length), backtrack through the dp table. When dp[i][j] came from dp[i-][j-] + , that character is in the LCS. Space optimization: you only need the previous row, so use two rows or a single row with careful updating.
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$ curl repovive.com/roadmaps/maang-interview-prep/dynamic-programming/lcs-implementation
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